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- f[xᵢ, xᵢ₊₁] = (f[xᵢ₊₁] − f[xᵢ])/(xᵢ₊₁ − xᵢ), and so on. Pₙ(x) = f[x₀] + f[x₀, x₁](x − x₀) + f[x₀, x₁, x₂](x − x₀)(x − x₁) + …
Memory trickAdding a new point only adds one new term: no
need to start over (unlike Lagrange).
🎯 How this can come up · 1 question
MCQ
With f(1) = 2, f(2) = 5, the first divided difference f[1, 2] is:
Correct: 3.
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- Equally spaced nodes: forward differences Δ and the binomial-coefficient form.
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