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- Newton: pₙ = pₙ₋₁ − f(pₙ₋₁)/f′(pₙ₋₁). Quadratic convergence near a simple root, but needs f′ and a good starting point.
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Written
One Newton step for f(x) = x² − 2 from p₀ = 1.
p₁ = 1 − (1 − 2)/(2·1) = 1.5.
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- Secant: replaces f′ with the slope through the last two points: pₙ = pₙ₋₁ − f(pₙ₋₁)(pₙ₋₁ − pₙ₋₂)/(f(pₙ₋₁) − f(pₙ₋₂)). No derivative needed.
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- False position: secant formula but keeps the two points that bracket the root (like bisection), so it always converges.
Memory trickNewton needs f′; secant drops f′; false
position = secant + bracketing.
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MCQ
Which method keeps the root bracketed at every step?
Correct: False position.
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