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- Least-squares solution x̂ minimizes ‖b − Ax‖. Solve the normal equations AᵀAx̂ = Aᵀb. Unique ⇔ A’s columns are independent ⇔ AᵀA invertible: x̂ = (AᵀA)⁻¹Aᵀb.
TipLeast-squares error = ‖b − Ax̂‖.
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The least-squares solutions of Ax = b are the solutions of:
Correct: AᵀAx = Aᵀb.
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- With A = QR: Rx̂ = Qᵀb (more stable numerically).
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