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- det A = Σ aᵢⱼCᵢⱼ along any row or column, with cofactor Cᵢⱼ = (−1)^(i+j) det Aᵢⱼ. Expand along the row/column with the most zeros.
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- Triangular matrix: det = product of the diagonal entries.
🎯 How this can come up · 1 question
MCQ
det of [[2, 5, 1], [0, 3, 7], [0, 0, −1]] is:
2·3·(−1).
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