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- For A = [[a, b], [c, d]]: A⁻¹ = (1/(ad − bc))·[[d, −b], [−c, a]], when ad − bc ≠ 0.
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MCQ
The inverse of [[2, 1], [5, 3]] is:
det = 1.
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- (A⁻¹)⁻¹ = A, (AB)⁻¹ = B⁻¹A⁻¹, (Aᵀ)⁻¹ = (A⁻¹)ᵀ.
Exam trap(AB)⁻¹ = B⁻¹A⁻¹: the order reverses.
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- Algorithm: row reduce [A | I]. If A reduces to I, the right block is A⁻¹; otherwise A is not invertible.
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- Invertible Matrix Theorem (n×n A): A invertible ⇔ n pivots ⇔ A ~ I ⇔ Ax = 0 has only the trivial solution ⇔ columns linearly independent ⇔ columns span ℝⁿ ⇔ Ax = b has a unique solution for every b ⇔ det A ≠ 0 ⇔ 0 is not an eigenvalue ⇔ rank A = n.
TipInvertible Matrix Theorem (n×n A): A invertible ⇔ n
pivots ⇔ A ~ I ⇔ Ax = 0 has only the trivial solution ⇔ columns
linearly independent ⇔ columns span ℝⁿ ⇔ Ax = b has a unique
solution for every b ⇔ det A ≠ 0 ⇔ 0 is not an eigenvalue ⇔ rank
A = n.
🎯 How this can come up · 1 question
True / False
If A is n×n and Ax = 0 has a nontrivial solution, then A is invertible.
False. It is NOT invertible.
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